Aldehydes, Ketones and Carboxylic Acids Chapter-Wise Test 4

Correct answer Carries: 4.

Wrong Answer Carries: -1.

Which reaction converts \( \ce{CH3CH2CHO} \) to \( \ce{CH3CH=CHCHO} \)?

Propanal (\( \ce{CH3CH2CHO} \)) undergoes aldol condensation with itself, forming an aldol product that dehydrates to but-2-enal (\( \ce{CH3CH=CHCHO} \)).

Clemmensen reduction
Cannizzaro reaction
Aldol condensation
Grignard reaction
3

Which reagent distinguishes between ethanal and benzaldehyde?

Fehling’s solution oxidizes aliphatic aldehydes like ethanal (\( \ce{CH3CHO} \)) to form a red precipitate, but does not react with aromatic aldehydes like benzaldehyde (\( \ce{C6H5CHO} \)).

Fehling’s solution
Iodoform reagent
2,4-DNP
Schiff’s reagent
1

What is the product when cyclohexanone reacts with \( \ce{NaBH4} \)?

\( \ce{NaBH4} \) reduces ketones to secondary alcohols. Cyclohexanone (\( \ce{C6H10O} \)) forms cyclohexanol (\( \ce{C6H11OH} \)).

Cyclohexane
Cyclohexanal
Cyclohexanol
Cyclohexene
3

Which compound is formed by the ozonolysis of 3-methyl-1-butene followed by hydrolysis?

Ozonolysis of 3-methyl-1-butene (\( \ce{CH2=CHCH(CH3)2} \)) cleaves the double bond, forming methanal (\( \ce{HCHO} \)) and 2-methylpropanal (\( \ce{(CH3)2CHCHO} \)).

Acetone
Ethanal
2-Methylpropanal
Propanal
3

Which reaction converts propanal to propan-1-ol?

Reduction of propanal (\( \ce{CH3CH2CHO} \)) with \( \ce{NaBH4} \) yields propan-1-ol (\( \ce{CH3CH2CH2OH} \)).

Oxidation with \( \ce{KMnO4} \)
Aldol condensation
Clemmensen reduction
Reduction with \( \ce{NaBH4} \)
4

What is the IUPAC name of \( \ce{CH3CH2CH2CHO} \)?

The compound has a 4-carbon chain with an aldehyde group, named butanal.

Propanal
Butanal
Butan-2-one
Pentanal
1

Which compound does not undergo aldol condensation?

Aldol condensation requires α-hydrogens. Methanal (\( \ce{HCHO} \)) has no α-hydrogens and thus undergoes Cannizzaro reaction instead.

Propanal
Methanal
2-Methylpentanal
Cyclohexanone
2

What is the product when 2-methylpropanal undergoes Cannizzaro reaction?

2-Methylpropanal (\( \ce{(CH3)2CHCHO} \)) has no α-hydrogens, so it undergoes Cannizzaro reaction, forming 2-methylpropanol (\( \ce{(CH3)2CHCH2OH} \)) and 2-methylpropanoate.

2-Methylpropanoic acid
2-Methylpropene
2-Methylpropanal
2-Methylpropanol
4

What is the product when heptan-4-one is reduced with \( \ce{NaBH4} \)?

\( \ce{NaBH4} \) reduces heptan-4-one (\( \ce{CH3CH2CH2COCH2CH2CH3} \)) to heptan-4-ol (\( \ce{CH3CH2CH2CH(OH)CH2CH2CH3} \)), a secondary alcohol.

Heptane
Heptan-3-ol
Heptan-4-ol
Heptanal
3

Which aldehyde forms an eight-carbon unsaturated carbonyl compound via self-aldol condensation?

Pentanal (\( \ce{CH3CH2CH2CH2CHO} \)) undergoes self-aldol condensation to form 2-propylhept-2-enal (\( \ce{CH3CH2CH2CH2CH=C(CH2CH2CH3)CHO} \)), an eight-carbon unsaturated aldehyde.

Propanal
Butanal
Pentanal
2-Methylpropanal
3

Performance Summary

Score:

Category Details
Total Attempts:
Total Skipped:
Total Wrong Answers:
Total Correct Answers:
Time Taken:
Average Time Taken per Question:
Accuracy:
0