Correct answer Carries: 4.
Wrong Answer Carries: -1.
The product of \( \ce{CH3CH2NH2} \) reacting with \( \ce{CHCl3} \) and alcoholic KOH is:
Ethylamine (\( \ce{CH3CH2NH2} \)) forms ethyl isocyanide (\( \ce{CH3CH2NC} \)) in the carbylamine reaction, as per the PDF’s chemical properties.
The order of basicity in gaseous phase for amines with the same alkyl group is:
In the gaseous phase, basicity increases with more alkyl groups due to electron donation: tertiary > secondary > primary, as per the PDF’s basicity section.
The geometry around nitrogen in \( \ce{CH3CH2NH2} \) is:
Ethylamine (\( \ce{CH3CH2NH2} \)) has \( sp^3 \) hybridized nitrogen with three sigma bonds and one lone pair, giving a pyramidal geometry, as per the PDF’s structure.
The weakest base among the following in aqueous solution is:
Aniline (\( \ce{C6H5NH2} \)) is the weakest due to resonance delocalizing the nitrogen lone pair, reducing basicity, as per the PDF.
The strongest base in aqueous solution among the following is:
Diethylamine (\( \ce{(CH3CH2)2NH} \)) has the highest basicity in water due to inductive and solvation effects, as per the PDF’s basicity discussion.
The reaction of \( \ce{C6H5CH2Cl} \) with \( \ce{NH3} \) produces:
Benzyl chloride (\( \ce{C6H5CH2Cl} \)) undergoes ammonolysis with \( \ce{NH3} \) to form benzylamine (\( \ce{C6H5CH2NH2} \)), as per the PDF’s preparation methods.
Which amine forms a product with no N-H bonds when reacted with \( \ce{CH3COCl} \)?
Secondary amines like \( \ce{(CH3CH2)2NH} \) form \( \ce{CH3CON(CH2CH3)2} \) with \( \ce{CH3COCl} \), which has no N-H bonds, as per the PDF’s chemical properties.
What is the IUPAC name of the compound \( \ce{CH3CH2NH2} \)?
The compound has a two-carbon chain with an amino group on the first carbon. In IUPAC nomenclature, primary amines are named as alkanamines by replacing the 'e' of the alkane with 'amine'. Thus, \( \ce{CH3CH2NH2} \) is ethanamine.
The number of hydrogen bonds a molecule of \( \ce{CH3CH2NH2} \) can form with water is:
Ethylamine (\( \ce{CH3CH2NH2} \)), a primary amine, has two N-H bonds to donate and one lone pair to accept, forming three hydrogen bonds with water, as per the PDF’s solubility discussion.
The shape of the nitrogen atom in \( \ce{CH3NHCH3} \) is:
In \( \ce{CH3NHCH3} \), nitrogen has three sigma bonds (two C, one H) and one lone pair, giving a pyramidal shape due to \( sp^3 \) hybridization, as per the PDF’s structure.
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