Correct answer Carries: 4.
Wrong Answer Carries: -1.
Which method avoids the formation of secondary amines when preparing \( \ce{CH3CH2NH2} \)?
Gabriel phthalimide synthesis selectively forms primary amines like \( \ce{CH3CH2NH2} \) without secondary byproducts, as per the PDF’s preparation methods.
The product of \( \ce{CH3CH2NH2} \) reacting with \( \ce{CH3COCl} \) is:
Ethylamine (\( \ce{CH3CH2NH2} \)) reacts with acetyl chloride (\( \ce{CH3COCl} \)) to form N-ethylacetamide (\( \ce{CH3CONHCH2CH3} \)), as per the PDF’s acetylation.
Which amine reacts with \( \ce{HNO2} \) at 273-278 K to produce an alcohol?
Primary aliphatic amines like \( \ce{CH3CH2CH2NH2} \) react with \( \ce{HNO2} \) to form alcohols (e.g., propan-1-ol) and \( \ce{N2} \), as described in the PDF’s chemical properties.
The product of \( \ce{CH3CH2NHCH3} \) with \( \ce{HNO2} \) is:
Secondary amines like \( \ce{CH3CH2NHCH3} \) form nitrosamines (e.g., \( \ce{CH3CH2N(NO)CH3} \)), a yellow oily liquid, with \( \ce{HNO2} \), as per the PDF’s chemical properties.
Which of the following is a tertiary amine?
A tertiary amine has three alkyl groups on nitrogen. \( \ce{(CH3CH2)3N} \) (triethylamine) fits this description, as per the PDF’s classification.
The solubility of amines in water is due to:
Amines dissolve in water due to hydrogen bonding between N-H bonds or the nitrogen lone pair and water molecules, as per the PDF’s physical properties.
Which of the following has the lowest boiling point?
Boiling point depends on hydrogen bonding. \( \ce{(CH3)3N} \) (tertiary amine) lacks hydrogen bonding, unlike \( \ce{CH3NH2} \) and \( \ce{CH3CH2NH2} \) (primary amines), and has a lower molar mass than \( \ce{C6H5NH2} \).
Which of the following is a correct order of boiling points?
Primary amines have higher boiling points than tertiary amines due to hydrogen bonding. Thus, \( \ce{CH3CH2NH2} \) (primary) > \( \ce{(CH3)3N} \) (tertiary), as per the PDF’s physical properties.
The reaction of \( \ce{CH3CH2NH2} \) with \( \ce{HCl} \) produces:
Ethylamine (\( \ce{CH3CH2NH2} \)), a base, reacts with \( \ce{HCl} \) to form ethylammonium chloride (\( \ce{CH3CH2NH3Cl} \)), as per the PDF’s basicity.
The weakest base among the following in aqueous solution is:
Aniline (\( \ce{C6H5NH2} \)) is the weakest base due to resonance delocalizing the nitrogen lone pair, reducing basicity, as per the PDF.
Are you sure you want to submit your answers?
