Correct answer Carries: 4.
Wrong Answer Carries: -1.
Which amine, when treated with \( \ce{CH3COCl} \), forms a compound with two nitrogen atoms?
None of the listed amines form a compound with two nitrogens with \( \ce{CH3COCl} \); however, if misinterpreted, \( \ce{CH3NH2} \) forms \( \ce{CH3NHCOCH3} \) (one N). Assuming a typo or contextual error, the intent might be a single N product, but all options yield one N. Correcting intent: primary amines like \( \ce{CH3NH2} \) react typically. Here, \( \ce{CH3NH2} \) is chosen for standard reaction.
Which amine would require the least amount of \( \ce{HCl} \) to form a salt per mole?
Tertiary amines like \( \ce{(CH3CH2)3N} \) have one lone pair and need only one mole of \( \ce{HCl} \) to form a salt, unlike primary or secondary amines with additional N-H bonds, as per the PDF’s basicity.
Which of the following is insoluble in alkali when reacted with Hinsberg’s reagent?
Secondary amines like \( \ce{(CH3)2NH} \) form sulphonamides with no acidic hydrogen, making them insoluble in alkali, unlike primary amine products.
Which of the following is a secondary amine?
A secondary amine has two alkyl or aryl groups attached to the nitrogen. Among the options, \( \ce{CH3NHCH3} \) has two methyl groups attached to nitrogen, making it a secondary amine (N-methylmethanamine).
The correct order of basic strength in aqueous solution is:
In aqueous solution, secondary amines like \( \ce{(CH3)2NH} \) are stronger bases than primary (\( \ce{CH3NH2} \)) and ammonia (\( \ce{NH3} \)) due to solvation and inductive effects, as per the PDF.
Which of the following is a product of the reduction of nitrobenzene using \( \ce{Sn/HCl} \)?
Reduction of nitrobenzene (\( \ce{C6H5NO2} \)) with \( \ce{Sn/HCl} \) yields aniline (\( \ce{C6H5NH2} \)), a primary aromatic amine, as per the PDF’s discussion on amine preparation.
A compound \( X \) on treatment with \( \ce{Br2} \) and \( \ce{KOH} \) yields \( \ce{CH3NH2} \). \( X \) is:
Ethanamide (\( \ce{CH3CONH2} \)) undergoes Hoffmann bromamide reaction with \( \ce{Br2} \) and \( \ce{KOH} \) to form methylamine (\( \ce{CH3NH2} \)), as per the PDF.
An amine \( X \) reacts with \( \ce{H2SO4} \) at 453-473 K to form \( \ce{H2NC6H4SO3H} \). \( X \) is:
Aniline (\( \ce{C6H5NH2} \)) undergoes sulphonation with \( \ce{H2SO4} \) at high temperature to form sulphanilic acid (\( \ce{H2NC6H4SO3H} \)), as per the PDF.
The reaction of aniline with \( \ce{H2SO4} \) at 453-473 K produces:
Aniline (\( \ce{C6H5NH2} \)) with \( \ce{H2SO4} \) at high temperature forms p-aminobenzene sulphonic acid (sulphanilic acid), as per the PDF’s chemical properties.
Which of the following amines has the highest basic strength in aqueous solution?
Basic strength depends on electron availability on nitrogen. \( \ce{(C2H5)2NH} \) (diethylamine) has two electron-donating ethyl groups and benefits from solvation effects, making it the strongest base among the options.
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