Correct answer Carries: 4.
Wrong Answer Carries: -1.
The basicity of amines is due to:
Amines are basic because the nitrogen lone pair can accept a proton, as explained in the PDF’s basicity section.
Which of the following amines has the lowest molecular weight?
Methylamine (\( \ce{CH3NH2} \)) has the smallest alkyl group (1 carbon) among the options, giving it the lowest molecular weight, as per the PDF’s classification.
Which amine produces a tertiary amine when treated with excess \( \ce{CH3CH2Cl} \)?
A primary amine like \( \ce{CH3NH2} \) can be dialkylated with excess \( \ce{CH3CH2Cl} \) to form \( \ce{CH3N(CH2CH3)2} \), a tertiary amine, as per the PDF’s alkylation.
Which amine can be prepared by Gabriel phthalimide synthesis?
Gabriel synthesis produces primary aliphatic amines like \( \ce{CH3CH2NH2} \) from alkyl halides, not aromatic amines, as per the PDF.
The reaction of \( \ce{CH3NH2} \) with \( \ce{HNO2} \) at 273-278 K yields:
Methylamine (\( \ce{CH3NH2} \)) reacts with \( \ce{HNO2} \) to form methanol (\( \ce{CH3OH} \)) and \( \ce{N2} \), as per the PDF’s chemical properties.
The number of isomers of \( \ce{C3H9N} \) that liberate nitrogen gas with nitrous acid is:
\( \ce{C3H9N} \) has four isomers: propan-1-amine, propan-2-amine, ethylmethylamine, and trimethylamine. Only primary amines (propan-1-amine and propan-2-amine) react with \( \ce{HNO2} \) to liberate \( \ce{N2} \), so the number is 2.
The strongest base among the following in gaseous phase is:
In the gaseous phase, basicity depends on electron donation to nitrogen. \( \ce{(CH3)3N} \) (tertiary amine) has three methyl groups, making it the strongest base, as noted in the PDF.
The boiling point of \( \ce{CH3CH2NH2} \) is higher than \( \ce{CH3CH3} \) because of:
Ethylamine (\( \ce{CH3CH2NH2} \)) forms hydrogen bonds, unlike ethane (\( \ce{CH3CH3} \)), which relies on weak van der Waals forces, as per the PDF’s physical properties.
Which amine forms a soluble product in alkali when reacted with Hinsberg’s reagent?
Primary amines like \( \ce{CH3CH2CH2NH2} \) form sulphonamides with an acidic hydrogen, soluble in alkali, as per the PDF’s Hinsberg test.
Which amine reacts with \( \ce{HNO2} \) to form \( \ce{CH3CH2OH} \) and \( \ce{N2} \)?
Ethylamine (\( \ce{CH3CH2NH2} \)) reacts with \( \ce{HNO2} \) to produce ethanol (\( \ce{CH3CH2OH} \)) and nitrogen gas, as per the PDF’s chemical properties.
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