Amines Chapter-Wise Test 3

Correct answer Carries: 4.

Wrong Answer Carries: -1.

The IUPAC name of \( \ce{CH3CH(NH2)CH3} \) is:

The compound has a three-carbon chain with an amino group on the second carbon. In IUPAC, it’s named propan-2-amine.

Propan-1-amine
Isopropylamine
N-Methylmethanamine
Propan-2-amine
4

Which method uses phthalimide to prepare primary amines?

Gabriel phthalimide synthesis uses phthalimide with an alkyl halide to selectively prepare primary amines, as detailed in the PDF.

Hoffmann bromamide reaction
Reduction of nitro compounds
Ammonolysis
Gabriel phthalimide synthesis
4

Which of the following amines does not liberate \( \ce{N2} \) gas with \( \ce{HNO2} \)?

Tertiary amines like \( \ce{(CH3CH2)3N} \) do not react with \( \ce{HNO2} \) to liberate \( \ce{N2} \), unlike primary aliphatic amines, as per the PDF.

\( \ce{CH3CH2NH2} \)
\( \ce{CH3CH2CH2NH2} \)
\( \ce{(CH3CH2)3N} \)
\( \ce{CH3NHCH3} \)
3

The hybridization of nitrogen in the product of \( \ce{CH3NH2} \) with \( \ce{CH3COCl} \) is:

\( \ce{CH3NH2} \) forms \( \ce{CH3NHCOCH3} \) with \( \ce{CH3COCl} \). Nitrogen has three sigma bonds and one lone pair, remaining \( sp^3 \), as per the PDF’s structure.

\( sp^2 \)
\( sp \)
\( sp^3 \)
\( dsp^2 \)
3

Which of the following has the least number of hydrogen atoms attached to nitrogen?

Tertiary amines like \( \ce{(CH3)3N} \) have no hydrogen atoms on nitrogen, unlike primary (2 H) and secondary (1 H) amines, as per the PDF.

\( \ce{CH3NH2} \)
\( \ce{(CH3)2NH} \)
\( \ce{C6H5NH2} \)
\( \ce{(CH3)3N} \)
4

The boiling point of \( \ce{(CH3)2NH} \) is lower than \( \ce{CH3CH2NH2} \) due to:

\( \ce{(CH3)2NH} \) (secondary) has one N-H bond, while \( \ce{CH3CH2NH2} \) (primary) has two, leading to less hydrogen bonding and a lower boiling point, as per the PDF.

Higher molecular weight
Resonance
Fewer hydrogen bonds
Steric hindrance
3

How many hydrogen atoms are directly attached to nitrogen in \( \ce{(CH3CH2)2NH} \)?

Diethylamine (\( \ce{(CH3CH2)2NH} \)), a secondary amine, has one hydrogen atom directly attached to nitrogen, as per the PDF’s structure.

2
0
1
3
3

What is the major product when aniline reacts with excess bromine water?

Aniline (\( \ce{C6H5NH2} \)) undergoes electrophilic substitution with excess bromine water, forming 2,4,6-tribromoaniline due to the strong activating effect of the \( \ce{-NH2} \) group.

\( \ce{C6H5Br} \)
2,4,6-Tribromoaniline
p-Bromoaniline
o-Bromoaniline
2

Which statement is true about the basicity of \( \ce{C6H5NH2} \) compared to \( \ce{CH3NH2} \)?

Aniline (\( \ce{C6H5NH2} \)) is less basic than methylamine (\( \ce{CH3NH2} \)) due to resonance delocalizing the nitrogen lone pair, as per the PDF’s basicity section.

\( \ce{C6H5NH2} \) is more basic due to resonance
\( \ce{C6H5NH2} \) is more basic due to inductive effect
\( \ce{C6H5NH2} \) is less basic due to resonance
\( \ce{C6H5NH2} \) is less basic due to steric hindrance
3

Which method is preferred for preparing primary amines without forming secondary or tertiary amines?

Gabriel phthalimide synthesis selectively produces primary amines by reacting phthalimide with an alkyl halide, followed by hydrolysis, avoiding mixtures of secondary and tertiary amines seen in ammonolysis.

Ammonolysis
Gabriel phthalimide synthesis
Reduction of nitro compounds
Hoffmann bromamide reaction
2

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