Amines Chapter-Wise Test 4

Correct answer Carries: 4.

Wrong Answer Carries: -1.

Which amine turns bromine water colorless due to substitution?

Aniline (\( \ce{C6H5NH2} \)) undergoes electrophilic substitution with \( \ce{Br2} \) in water, forming 2,4,6-tribromoaniline and decolorizing bromine, as per the PDF.

\( \ce{CH3NH2} \)
\( \ce{C6H5NH2} \)
\( \ce{(CH3)2NH} \)
\( \ce{(CH3CH2)3N} \)
2

A primary amine \( X \) reacts with \( \ce{HNO2} \) to give \( \ce{CH3CH2CH2CH2OH} \). \( X \) is:

Butan-1-amine (\( \ce{CH3CH2CH2CH2NH2} \)) reacts with \( \ce{HNO2} \) to form butan-1-ol (\( \ce{CH3CH2CH2CH2OH} \)) and \( \ce{N2} \), as per the PDF.

\( \ce{CH3CH2NH2} \)
\( \ce{CH3CH2CH2NH2} \)
\( \ce{C6H5NH2} \)
\( \ce{CH3CH2CH2CH2NH2} \)
4

An amine \( X \) reacts with \( \ce{CH3CH2Cl} \) to form a tertiary amine. \( X \) could be:

A secondary amine like \( \ce{CH3NHCH3} \) reacts with \( \ce{CH3CH2Cl} \) to add an ethyl group, forming a tertiary amine (\( \ce{CH3CH2N(CH3)2} \)), as per the PDF’s alkylation.

\( \ce{CH3CH2NH2} \)
\( \ce{CH3NHCH3} \)
\( \ce{(CH3)3N} \)
\( \ce{C6H5NH2} \)
2

Which amine produces a yellow oily liquid on reaction with \( \ce{HNO2} \)?

Secondary amines like \( \ce{(CH3CH2)2NH} \) react with \( \ce{HNO2} \) to form yellow oily nitrosamines (e.g., \( \ce{(CH3CH2)2N-NO} \)), as described in the PDF’s chemical tests.

\( \ce{CH3CH2NH2} \)
\( \ce{C6H5NH2} \)
\( \ce{(CH3CH2)2NH} \)
\( \ce{(CH3)3N} \)
3

The number of lone pairs on nitrogen in \( \ce{(CH3)3N} \) is:

In trimethylamine (\( \ce{(CH3)3N} \)), nitrogen has three sigma bonds to carbon and one lone pair, as per the PDF’s structure section.

2
0
1
3
3

The number of lone pairs on nitrogen in \( \ce{CH3CH2NHCH3} \) is:

In \( \ce{CH3CH2NHCH3} \), nitrogen has three sigma bonds (two C, one H) and one lone pair, as per the PDF’s structure.

2
0
1
3
3

The product of \( \ce{CH3CH2NH2} \) with \( \ce{CH3CH2CH2COCl} \) is:

Ethylamine (\( \ce{CH3CH2NH2} \)) reacts with butanoyl chloride (\( \ce{CH3CH2CH2COCl} \)) to form N-ethylbutanamide (\( \ce{CH3CH2CH2CONHCH2CH3} \)), as per the PDF’s acylation.

\( \ce{CH3CH2NHCH2CH2CH3} \)
\( \ce{CH3CH2CH2CONHCH2CH3} \)
\( \ce{CH3CH2CH2COOH} \)
\( \ce{CH3CH2CH2NH2} \)
2

An amine \( X \) reacts with \( \ce{CHCl3} \) and KOH to form \( \ce{CH3CH2NC} \). \( X \) is:

Ethylamine (\( \ce{CH3CH2NH2} \)) forms ethyl isocyanide (\( \ce{CH3CH2NC} \)) in the carbylamine reaction, as per the PDF’s chemical properties.

\( \ce{CH3NH2} \)
\( \ce{CH3CH2NH2} \)
\( \ce{(CH3CH2)2NH} \)
\( \ce{(CH3)3N} \)
2

The basic strength of aniline is less than aliphatic amines due to:

Resonance in aniline delocalizes the nitrogen lone pair into the benzene ring, reducing basicity compared to aliphatic amines, as per the PDF.

Inductive effect
Steric hindrance
Hydrogen bonding
Resonance
4

Which amine does not react with benzenesulphonyl chloride?

Tertiary amines like \( \ce{(CH3CH2)3N} \) lack a hydrogen on nitrogen to form sulphonamides with benzenesulphonyl chloride, unlike primary and secondary amines.

\( \ce{CH3NH2} \)
\( \ce{(CH3)2NH} \)
\( \ce{(CH3CH2)3N} \)
\( \ce{C6H5NH2} \)
3

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