Correct answer Carries: 4.
Wrong Answer Carries: -1.
Which amine requires the least number of steps to prepare from \( \ce{CH3Cl} \) using \( \ce{NH3} \)?
Methylamine (\( \ce{CH3NH2} \)) is formed directly from \( \ce{CH3Cl} \) and \( \ce{NH3} \) in one step via ammonolysis, as per the PDF’s preparation methods.
The compound formed when ethylamine reacts with chloroform and alcoholic KOH is:
Ethylamine (\( \ce{CH3CH2NH2} \)) undergoes the carbylamine reaction with \( \ce{CHCl3} \) and alcoholic KOH to form ethyl isocyanide (\( \ce{CH3CH2NC} \)), as per the PDF.
The hybridization of nitrogen in \( \ce{(CH3CH2)3N} \) is:
In triethylamine (\( \ce{(CH3CH2)3N} \)), nitrogen has three sigma bonds to carbon and one lone pair, indicating \( sp^3 \) hybridization, as per the PDF’s structure.
The weakest base in aqueous solution among the following is:
Aniline (\( \ce{C6H5NH2} \)) is the weakest due to resonance delocalizing the nitrogen lone pair, as per the PDF’s basicity discussion.
The strongest base in gaseous phase among the following is:
Trimethylamine (\( \ce{(CH3)3N} \)) has three electron-donating methyl groups, making it the strongest base in the gaseous phase, as per the PDF.
Which of the following is not a physical property of amines?
Reaction with \( \ce{HNO2} \) is a chemical property, not a physical one like boiling point or solubility, as per the PDF’s physical properties section.
Which amine gives a foul-smelling compound on reaction with \( \ce{CHCl3} \) and alcoholic KOH?
Primary amines like \( \ce{CH3NH2} \) react with \( \ce{CHCl3} \) and alcoholic KOH to form isocyanides (e.g., \( \ce{CH3NC} \)), which have a foul odor, as per the PDF’s carbylamine test.
Which of the following is a primary aliphatic amine?
Ethylamine (\( \ce{CH3CH2NH2} \)) has one alkyl group attached to nitrogen and no aryl group, making it a primary aliphatic amine, as per the PDF’s classification.
Which compound is formed when benzyl chloride undergoes ammonolysis followed by reaction with two moles of \( \ce{CH3Cl} \)?
Benzyl chloride (\( \ce{C6H5CH2Cl} \)) with \( \ce{NH3} \) forms benzylamine (\( \ce{C6H5CH2NH2} \)), which reacts with two \( \ce{CH3Cl} \) to form \( \ce{C6H5CH2N(CH3)2} \) (N,N-dimethylbenzylamine).
Which property of aniline allows it to undergo electrophilic substitution at ortho and para positions?
The \( \ce{-NH2} \) group in aniline is electron-donating due to resonance, activating the ring and directing substitution to ortho and para positions, as per the PDF.
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