Correct answer Carries: 4.
Wrong Answer Carries: -1.
Which of the following is an aromatic amine?
Aniline (\( \ce{C6H5NH2} \)) has the \( \ce{-NH2} \) group directly attached to a benzene ring, classifying it as an aromatic amine, as per the PDF.
Which of the following amines is most soluble in water?
Solubility decreases with increasing alkyl chain length due to reduced hydrogen bonding. \( \ce{CH3NH2} \) (smallest chain) is most soluble, as per the PDF’s physical properties.
Which reaction of \( \ce{CH3NH2} \) produces a compound with a characteristic foul odor?
The carbylamine reaction of \( \ce{CH3NH2} \) with \( \ce{CHCl3} \) and KOH forms methyl isocyanide (\( \ce{CH3NC} \)), known for its foul odor, as per the PDF.
Which physical property decreases as the amine order increases from primary to tertiary?
Hydrogen bonding decreases from primary (two N-H) to secondary (one N-H) to tertiary (no N-H), as per the PDF’s physical properties.
An amide \( X \) on Hoffmann bromamide reaction gives \( \ce{CH3CH2NH2} \). \( X \) is:
Propanamide (\( \ce{CH3CH2CONH2} \)) loses one carbon in the Hoffmann reaction to form ethylamine (\( \ce{CH3CH2NH2} \)), as per the PDF.
The product of \( \ce{CH3CH2NH2} \) reacting with excess \( \ce{CH3Cl} \) is:
Ethylamine (\( \ce{CH3CH2NH2} \)) with excess \( \ce{CH3Cl} \) undergoes alkylation to form \( \ce{CH3CH2N(CH3)2} \) (N,N-dimethylethylamine), a tertiary amine, as per the PDF.
Which method selectively produces primary amines without secondary or tertiary byproducts?
Gabriel phthalimide synthesis produces only primary amines by reacting phthalimide with an alkyl halide, as per the PDF’s preparation methods.
An alkyl halide \( X \) reacts with \( \ce{NH3} \) to give \( \ce{CH3CH2CH2NH2} \). \( X \) is:
1-Chloropropane (\( \ce{CH3CH2CH2Cl} \)) undergoes ammonolysis with \( \ce{NH3} \) to form propan-1-amine (\( \ce{CH3CH2CH2NH2} \)), as per the PDF’s preparation methods.
The product of \( \ce{CH3CH2CH2NH2} \) with \( \ce{CH3CH2Cl} \) in the presence of a base is:
Propan-1-amine (\( \ce{CH3CH2CH2NH2} \)) reacts with \( \ce{CH3CH2Cl} \) and a base to form N-ethylpropan-1-amine (\( \ce{CH3CH2CH2NHCH2CH3} \)), as per the PDF’s alkylation.
The product of \( \ce{CH3CH2CH2CH2NO2} \) reduction with \( \ce{H2/Ni} \) is:
Reduction of 1-nitrobutane (\( \ce{CH3CH2CH2CH2NO2} \)) with \( \ce{H2/Ni} \) yields butan-1-amine (\( \ce{CH3CH2CH2CH2NH2} \)), as per the PDF’s preparation methods.
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