Correct answer Carries: 4.
Wrong Answer Carries: -1.
The product of \( \ce{C6H5NH2} \) reacting with one mole of \( \ce{CH3COCl} \) is:
Aniline (\( \ce{C6H5NH2} \)) reacts with one mole of acetyl chloride to form acetanilide (\( \ce{C6H5NHCOCH3} \)), as per the PDF’s acetylation reaction.
Which test produces a foul odor with primary aliphatic amines?
The carbylamine test (\( \ce{CHCl3} \) + alcoholic KOH) with primary aliphatic amines forms isocyanides, which have a foul odor, as per the PDF’s chemical properties.
Aniline on nitration gives a significant amount of:
In strong acidic medium, aniline protonates to form anilinium ion, which is meta-directing, leading to substantial m-nitroaniline alongside ortho and para isomers.
The strongest base in gaseous phase among the following is:
In the gaseous phase, tertiary amines like \( \ce{(CH3CH2)3N} \) have the highest basicity due to maximum electron donation from three alkyl groups, as per the PDF.
The hybridization of nitrogen in \( \ce{CH3NH2} \) is:
In methylamine (\( \ce{CH3NH2} \)), nitrogen is bonded to one carbon and two hydrogens, with a lone pair, resulting in \( sp^3 \) hybridization, as noted in the PDF’s structure section.
The IUPAC name of \( \ce{CH3N(CH2CH3)2} \) is:
For tertiary amines, the largest alkyl group is the parent. Here, ethanamine with N-methyl and N-ethyl substituents is N-ethyl-N-methylethanamine, as per the PDF.
Which amine can be prepared by reducing \( \ce{CH3CH2NO2} \) with \( \ce{H2/Ni} \)?
Reduction of nitroethane (\( \ce{CH3CH2NO2} \)) with \( \ce{H2/Ni} \) yields ethylamine (\( \ce{CH3CH2NH2} \)), as per the PDF’s preparation methods.
Which amine forms a sulphonamide insoluble in alkali with \( \ce{C6H5SO2Cl} \)?
Secondary amines like \( \ce{(CH3CH2)2NH} \) form sulphonamides lacking an acidic hydrogen, insoluble in alkali, as per the PDF’s Hinsberg test.
The product of \( \ce{CH3CH2NH2} \) reacting with \( \ce{HNO2} \) at 273-278 K is:
Ethylamine (\( \ce{CH3CH2NH2} \)) reacts with \( \ce{HNO2} \) to form ethanol (\( \ce{CH3CH2OH} \)) and \( \ce{N2} \), as per the PDF’s chemical properties.
The product of the reaction \( \ce{CH3CH2NH2 + HCl ->} \) is:
Ethanamine, a basic amine, reacts with HCl to form its salt, ethylammonium chloride (\( \ce{CH3CH2NH3^+ Cl^-} \)).
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