Correct answer Carries: 4.
Wrong Answer Carries: -1.
Which amine has the highest boiling point?
Primary amines like \( \ce{CH3CH2CH2NH2} \) have stronger hydrogen bonding than secondary or tertiary amines, leading to a higher boiling point, as per the PDF.
The IUPAC name of \( \ce{(CH3)2NCH2CH3} \) is:
For tertiary amines, the largest alkyl group is the parent chain. Here, ethyl (\( \ce{CH2CH3} \)) is the parent, with two methyl groups on nitrogen, named N,N-dimethylethanamine, as per the PDF.
The reaction of \( \ce{CH3NH2} \) with \( \ce{HNO2} \) produces:
Methylamine (\( \ce{CH3NH2} \)), a primary aliphatic amine, reacts with \( \ce{HNO2} \) to form methanol (\( \ce{CH3OH} \)) and \( \ce{N2} \), as per the PDF.
Which compound is formed when \( \ce{CH3CH2CONH2} \) reacts with \( \ce{Br2} \) and \( \ce{KOH} \)?
Hoffmann bromamide reaction converts \( \ce{CH3CH2CONH2} \) (propanamide) to \( \ce{CH3CH2NH2} \) (ethylamine), reducing the carbon chain by one, as per the PDF.
Which amine can be separated from a mixture using the Hinsberg test with alkali?
Primary amines like \( \ce{CH3CH2NH2} \) form sulphonamides soluble in alkali, allowing separation, as per the PDF’s Hinsberg test.
The boiling point of \( \ce{CH3NH2} \) is higher than \( \ce{(CH3)3N} \) due to:
\( \ce{CH3NH2} \) (primary) forms hydrogen bonds, while \( \ce{(CH3)3N} \) (tertiary) does not, leading to a higher boiling point for the former, as per the PDF.
Which amine cannot be prepared by Gabriel phthalimide synthesis?
Aromatic amines like \( \ce{C6H5NH2} \) cannot be prepared by Gabriel synthesis, which is limited to aliphatic primary amines, as per the PDF.
The reaction of aniline with concentrated \( \ce{H2SO4} \) at 453-473 K produces:
Aniline forms anilinium hydrogensulphate, which rearranges on heating to p-aminobenzene sulphonic acid (sulphanilic acid).
Which property explains the basic nature of amines?
The lone pair on nitrogen allows amines to accept a proton, making them basic, as per the PDF’s basicity section.
The number of sigma bonds around nitrogen in \( \ce{CH3NH2} \) is:
In methylamine (\( \ce{CH3NH2} \)), nitrogen forms one sigma bond with carbon and two with hydrogens, totaling three, as per the PDF’s structure.
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