Chemical Bonding and Molecular Structure Chapter-Wise Test 5

Correct answer Carries: 4.

Wrong Answer Carries: -1.

The hybridization of nitrogen in \( \ce{NF3} \) is:

In \( \ce{NF3} \), nitrogen has 4 electron pairs (3 bonding, 1 lone), requiring \( sp^3 \) hybridization, forming a trigonal pyramidal shape.

\( sp^2 \)
\( sp \)
\( sp^3d \)
\( sp^3 \)
4

The shape of \( \ce{SCl2} \) molecule is:

In \( \ce{SCl2} \), sulfur is \( sp^3 \) hybridized with 4 electron pairs (2 bonding, 2 lone), resulting in a bent shape.

Linear
Trigonal pyramidal
Tetrahedral
Bent
4

In which compound does the central atom have a lone pair affecting its geometry?

In \( \ce{NH3} \), nitrogen has one lone pair in its \( sp^3 \) hybridized state, reducing the bond angle to 107° and giving a pyramidal shape.

\( \ce{NH3} \)
\( \ce{CH4} \)
\( \ce{BF3} \)
\( \ce{CO2} \)
1

Which molecule has a tetrahedral electron pair geometry but a bent molecular shape?

In \( \ce{H2S} \), sulfur has 4 electron pairs (2 bonding, 2 lone), giving a tetrahedral electron geometry (\( sp^3 \)), but a bent shape due to lone pairs.

\( \ce{H2S} \)
\( \ce{NH3} \)
\( \ce{CH4} \)
\( \ce{BF3} \)
1

The hybridization of tellurium in \( \ce{TeF6} \) is:

In \( \ce{TeF6} \), tellurium has 6 bonding pairs and no lone pairs, requiring \( sp^3d^2 \) hybridization, forming an octahedral shape.

\( sp^3d \)
\( sp^3 \)
\( sp^3d^3 \)
\( sp^3d^2 \)
4

Which molecule has a T-shaped molecular geometry?

In \( \ce{ClF3} \), chlorine is \( sp^3d \) hybridized with 5 electron pairs (3 bonding, 2 lone), resulting in a T-shaped geometry.

\( \ce{XeF4} \)
\( \ce{ClF3} \)
\( \ce{PF5} \)
\( \ce{SF6} \)
2

Which molecule has a bond angle of approximately 180° due to a triple bond and no lone pairs on the central atom?

In \( \ce{C2H2} \) (ethyne), each carbon is \( sp \) hybridized with a triple bond, resulting in a linear shape and 180° bond angle.

\( \ce{CO2} \)
\( \ce{C2H2} \)
\( \ce{SO2} \)
\( \ce{NH3} \)
2

The bond angle in \( \ce{SO2} \) is approximately:

In \( \ce{SO2} \), sulfur is \( sp^2 \) hybridized with one lone pair, reducing the bond angle to about 119° due to lone pair-bond pair repulsion.

109.5°
180°
119°
90°
3

The number of pi bonds in \( \ce{C6H6} \) (benzene) is:

In benzene (\( \ce{C6H6} \)), there are 6 \( \ce{C-C} \) sigma bonds, 6 \( \ce{C-H} \) sigma bonds, and 3 pi bonds from alternating double bonds in its ring structure.

6
3
4
2
2

Which species is diamagnetic and has a bond order of 3?

For \(\ce{N2}\) (14 electrons): \((\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\sigma 2p_z)^2\). Bonding = 10, antibonding = 4. Bond order = \(\frac{10 - 4}{2} = 3\), with all electrons paired, making it diamagnetic.

\(\ce{NO}\)
\(\ce{N2}\)
\(\ce{B2}\)
\(\ce{O2}\)
2

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