Coordination Compounds Chapter-Wise Test 10

Correct answer Carries: 4.

Wrong Answer Carries: -1.

Which complex has a square planar geometry due to strong field ligands?

\( \ce{[Ni(CN)4]^2-} \) (Ni\(^{2+}\), \( d^8 \)) with strong field \( \ce{CN^-} \) adopts square planar geometry (\( dsp^2 \)).

\( \ce{[NiCl4]^2-} \)
\( \ce{[CuCl4]^2-} \)
\( \ce{[Fe(H2O)4]^2+} \)
\( \ce{[Ni(CN)4]^2-} \)
4

What is the IUPAC name of \( \ce{[Cr(H2O)4Cl2]NO3} \)?

Ligands: aqua (\( \ce{H2O} \)), chlorido (\( \ce{Cl} \)), alphabetically ordered. Cr’s oxidation state is +3 (since \( \ce{[Cr(H2O)4Cl2]^+} \) balances \( \ce{NO3^-} \)). Name: tetraaquadichloridochromium(III) nitrate.

Tetraaquachloridochromium(III) nitrate
Dichloridotetraaquachromium(II) nitrate
Tetraaquadichloridochromium(III) nitrato
Tetraaquadichloridochromium(III) nitrate
4

What is the color of \( \ce{[Ti(H2O)6]^3+} \) in aqueous solution?

\( \ce{[Ti(H2O)6]^3+} \) (Ti\(^{3+}\), \( d^1 \)) absorbs blue-green light (498 nm) due to \( t_{2g} \) to \( e_g \) transition, appearing violet (complementary color).

Yellow
Blue
Violet
Green
3

Which ligand causes the largest crystal field splitting in a tetrahedral field?

From the spectrochemical series (\( \ce{Cl^-} < \ce{F^-} < \ce{NH3} < \ce{CN^-} \)), \( \ce{CN^-} \) is the strongest field ligand, causing the largest \( \Delta_t \).

\( \ce{Cl^-} \)
\( \ce{F^-} \)
\( \ce{CN^-} \)
\( \ce{NH3} \)
3

What is the total number of donor atoms in the ligands of \( \ce{[Ni(en)(NH3)2(H2O)]^2+} \)?

en (bidentate) has 2 donor atoms, 2 \( \ce{NH3} \) (unidentate) have 2, and 1 \( \ce{H2O} \) (unidentate) has 1. Total = 2 + 2 + 1 = 5.

5
4
6
3
1

How many electrons occupy the \( t_{2g} \) orbitals in \( \ce{[Cr(NH3)6]^3+} \)? (Cr atomic number = 24)

Cr\(^{3+}\) (\( d^3 \)) in \( \ce{[Cr(NH3)6]^3+} \) (octahedral) with moderate field \( \ce{NH3} \) has \( t_{2g}^3 \), so 3 electrons.

2
3
4
0
2

How many unpaired electrons are present in \( \ce{[CoF6]^3-} \)? (Co atomic number = 27)

Co\(^{3+}\) (\( d^6 \)) in \( \ce{[CoF6]^3-} \) (octahedral) with weak field \( \ce{F^-} \) is high spin: \( t_{2g}^4 e_g^2 \), giving 4 unpaired electrons.

2
4
0
6
2

How many moles of \( \ce{AgCl} \) precipitate when 1 mole of \( \ce{[Cr(H2O)5Cl]Cl2} \) reacts with excess \( \ce{AgNO3} \)?

In \( \ce{[Cr(H2O)5Cl]Cl2} \), the 2 \( \ce{Cl^-} \) ions outside the coordination sphere are ionizable and form \( \ce{AgCl} \), while the inner \( \ce{Cl} \) is a ligand. Thus, 2 moles precipitate.

2
1
3
0
1

How many moles of \( \ce{AgCl} \) are precipitated when 1 mole of \( \ce{[CoCl(NH3)5]Cl2} \) is treated with excess \( \ce{AgNO3} \)?

In \( \ce{[CoCl(NH3)5]Cl2} \), the two \( \ce{Cl^-} \) ions outside the coordination sphere are ionizable and precipitate as \( \ce{AgCl} \). The \( \ce{Cl} \) inside is bonded to Co and does not precipitate. Thus, 2 moles of \( \ce{AgCl} \) form.

2
1
3
0
1

What is the geometry of \( \ce{[Cu(NH3)4]^2+} \)?

\( \ce{[Cu(NH3)4]^2+} \) (Cu\(^{2+}\), \( d^9 \)) with 4 ligands adopts a square planar geometry due to \( dsp^2 \) hybridization, common for Cu(II) complexes.

Tetrahedral
Square planar
Octahedral
Linear
2

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