Coordination Compounds Chapter-Wise Test 2

Correct answer Carries: 4.

Wrong Answer Carries: -1.

What is the ratio of unidentate to bidentate ligands in \( \ce{[Co(NH3)3(en)Cl]^2+} \)?

In \( \ce{[Co(NH3)3(en)Cl]^2+} \), unidentate ligands = 3 \( \ce{NH3} \) + 1 \( \ce{Cl^-} \) = 4; bidentate = 1 en. Ratio = 4 : 1.

4 : 1
3 : 1
2 : 1
1 : 1
1

What is the geometry of \( \ce{[CoF4]^2-} \)?

\( \ce{[CoF4]^2-} \) (Co\(^{2+}\), \( d^7 \)) with 4 ligands is tetrahedral, using \( sp^3 \) hybridization due to weak field \( \ce{F^-} \).

Square planar
Tetrahedral
Octahedral
Linear
2

Which of the following is a homoleptic complex?

\( \ce{[Fe(H2O)6]^2+} \) has only one type of ligand (\( \ce{H2O} \)), making it homoleptic, unlike \( \ce{[Fe(H2O)5Cl]^+} \) with two types.

\( \ce{[Fe(H2O)5Cl]^+} \)
\( \ce{[Fe(H2O)6]^2+} \)
\( \ce{[Co(NH3)4Cl2]^+} \)
\( \ce{[Cr(NH3)2Cl4]^-} \)
2

Which complex has a metal ion that becomes diamagnetic when coordinated with 6 \( \ce{CN^-} \) ligands?

\( \ce{[Fe(H2O)6]^2+} \) (Fe\(^{2+}\), \( d^6 \)) is high spin with \( \ce{H2O} \) (4 unpaired electrons). With 6 \( \ce{CN^-} \) (strong field), it becomes \( \ce{[Fe(CN)6]^4-} \), low spin (0 unpaired electrons).

\( \ce{[Ni(H2O)6]^2+} \)
\( \ce{[CoF6]^3-} \)
\( \ce{[Fe(H2O)6]^2+} \)
\( \ce{[Cr(H2O)6]^3+} \)
3

What is the geometry of the coordination sphere in \( \ce{[Ni(en)2]^2+} \)?

\( \ce{[Ni(en)2]^2+} \) (Ni\(^{2+}\), \( d^8 \)) with 2 bidentate en (4 donor atoms) is square planar, using \( dsp^2 \) hybridization.

Tetrahedral
Octahedral
Square planar
Linear
2

The hybridization of cobalt in \( \ce{[CoF6]^3-} \) is:

\( \ce{[CoF6]^3-} \) (Co\(^{3+}\), \( d^6 \)) with weak field \( \ce{F^-} \) in an octahedral field is high spin, using outer orbitals (\( sp^3d^2 \)).

\( d^2sp^3 \)
\( sp^3d^2 \)
\( dsp^2 \)
\( sp^3 \)
2

Which complex has a metal ion with a \( d^7 \) configuration in an octahedral field that is high spin?

\( \ce{[Co(H2O)6]^2+} \) (Co\(^{2+}\), \( d^7 \)) with weak field \( \ce{H2O} \) in an octahedral field is high spin (\( t_{2g}^5 e_g^2 \)).

\( \ce{[Co(CN)6]^3-} \)
\( \ce{[Co(H2O)6]^2+} \)
\( \ce{[Ni(NH3)6]^2+} \)
\( \ce{[Fe(H2O)6]^3+} \)
2

Which complex has a secondary valence of 4 according to Werner’s theory?

Secondary valence is the coordination number. \( \ce{[Cu(NH3)4]SO4} \) has 4 \( \ce{NH3} \) ligands, giving a coordination number of 4.

\( \ce{[Cu(NH3)4]SO4} \)
\( \ce{[Co(NH3)6]Cl3} \)
\( \ce{[Fe(H2O)6]^2+} \)
\( \ce{[Cr(en)3]^3+} \)
1

The EAN of Co in \( \ce{[Co(NH3)6]^3+} \) is: (Co atomic number = 27)

Co\(^{3+}\) with 6 \( \ce{NH3} \) ligands. EAN = 27 - 3 + 2 × 6 = 36.

34
32
36
38
3

The magnetic moment of \( \ce{[MnCl4]^2-} \) is approximately: (Mn atomic number = 25)

Mn\(^{2+}\) (\( d^5 \)) in tetrahedral \( \ce{[MnCl4]^2-} \) (\( sp^3 \)) with weak field \( \ce{Cl^-} \) ligands is high spin (5 unpaired electrons). Magnetic moment = \( \sqrt{n(n+2)} = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \) BM.

1.73 BM
3.87 BM
4.90 BM
5.92 BM
4

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