Coordination Compounds Chapter-Wise Test 8

Correct answer Carries: 4.

Wrong Answer Carries: -1.

Which complex shows geometrical isomerism?

\( \ce{[Fe(H2O)4Cl2]^+} \) (octahedral, \( \ce{[Ma4b2]} \)) has 4 \( \ce{H2O} \) and 2 \( \ce{Cl^-} \), allowing cis and trans isomers.

\( \ce{[Fe(CN)6]^4-} \)
\( \ce{[Fe(H2O)4Cl2]^+} \)
\( \ce{[Ni(CO)4]} \)
\( \ce{[Co(NH3)6]^3+} \)
2

What type of isomerism is shown by \( \ce{[Co(NH3)5SO4]Br} \) and \( \ce{[Co(NH3)5Br]SO4} \)?

These complexes differ by exchanging \( \ce{Br^-} \) and \( \ce{SO4^2-} \) between the coordination sphere and counter ion, exhibiting ionization isomerism.

Geometrical
Linkage
Ionization
Optical
2

Which complex has a metal ion with an oxidation state equal to the number of unidentate ligands?

In \( \ce{[Co(NH3)3Cl3]} \), Co is +3 (neutral complex, 3 \( \ce{Cl^-} \) balanced), and there are 3 unidentate \( \ce{NH3} \) ligands, matching the oxidation state.

\( \ce{[Co(NH3)3Cl3]} \)
\( \ce{[Ni(NH3)4]^2+} \)
\( \ce{[Cu(H2O)4]^2+} \)
\( \ce{[Fe(H2O)6]^3+} \)
1

Which ligand is ambidentate?

An ambidentate ligand can bind through two different atoms. \( \ce{SCN^-} \) can coordinate via S or N, making it ambidentate, unlike \( \ce{Cl^-} \) or \( \ce{NH3} \) (unidentate).

\( \ce{Cl^-} \)
\( \ce{NH3} \)
\( \ce{SCN^-} \)
\( \ce{H2O} \)
3

Which complex can exhibit optical isomerism?

\( \ce{[Cr(en)2(H2O)2]^3+} \) (octahedral) with 2 bidentate en and 2 \( \ce{H2O} \) can form a cis isomer that is chiral, lacking symmetry.

\( \ce{[Cr(NH3)6]^3+} \)
\( \ce{[NiCl4]^2-} \)
\( \ce{[Cr(en)2(H2O)2]^3+} \)
\( \ce{[Cu(NH3)4]^2+} \)
3

What hybridization does the metal adopt in \( \ce{[Fe(CO)5]} \)?

\( \ce{[Fe(CO)5]} \) (Fe\(^0\), \( d^8 \)) with 5 ligands is trigonal bipyramidal, using \( dsp^3 \) hybridization.

\( sp^3d^2 \)
\( dsp^3 \)
\( d^2sp^3 \)
\( sp^3 \)
2

Which ligand in \( \ce{[Co(NH3)5SCN]^2+} \) can lead to linkage isomerism?

\( \ce{SCN^-} \) is ambidentate, binding via S (thiocyanato) or N (isothiocyanato), leading to linkage isomerism.

\( \ce{NH3} \)
\( \ce{SCN^-} \)
Both \( \ce{NH3} \) and \( \ce{SCN^-} \)
None
2

The hybridization of chromium in \( \ce{[Cr(H2O)6]^3+} \) is:

\( \ce{[Cr(H2O)6]^3+} \) (Cr\(^{3+}\), \( d^3 \)) is octahedral, using inner d orbitals with \( \ce{H2O} \) (\( d^2sp^3 \)).

\( sp^3d^2 \)
\( d^2sp^3 \)
\( sp^3 \)
\( dsp^2 \)
2

Which pair exhibits linkage isomerism?

\( \ce{[Cr(H2O)5CN]^2+} \) and \( \ce{[Cr(H2O)5NC]^2+} \) differ by the binding atom of the ambidentate \( \ce{CN^-} \) ligand (C vs. N).

\( \ce{[Cr(NH3)6]^3+} \) and \( \ce{[Cr(H2O)6]^3+} \)
\( \ce{[Cr(H2O)4Cl2]^+} \) (cis and trans)
\( \ce{[Cr(NH3)5Cl]SO4} \) and \( \ce{[Cr(NH3)5SO4]Cl} \)
\( \ce{[Cr(H2O)5CN]^2+} \) and \( \ce{[Cr(H2O)5NC]^2+} \)
4

What is the hybridization of Fe in \( \ce{[Fe(CN)6]^3-} \)?

\( \ce{[Fe(CN)6]^3-} \) (Fe\(^{3+}\), \( d^5 \)) with strong field \( \ce{CN^-} \) in an octahedral field is low spin, using inner d orbitals (\( d^2sp^3 \)).

\( sp^3d^2 \)
\( sp^3 \)
\( dsp^2 \)
\( d^2sp^3 \)
4

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