Haloalkanes and Haloarenes Chapter-Wise Test 9

Correct answer Carries: 4.

Wrong Answer Carries: -1.

What is the product when \( \ce{CH3CH2CHClCH2CH3} \) reacts with \( \ce{NaNH2} \) in liquid ammonia?

\( \ce{NaNH2} \) (strong base) promotes E2 elimination in \( \ce{CH3CH2CHClCH2CH3} \), forming \( \ce{CH3CH2CH=CHCH3} \) (2-pentene) per Zaitsev’s rule.

\( \ce{CH3CH2CH2CH2CH3} \)
\( \ce{CH3CH2CH2CH2NH2} \)
\( \ce{CH3CH2CH2CH=CH2} \)
\( \ce{CH3CH2CH=CHCH3} \)
4

Which alkene reacts with \( \ce{HCl} \) to form a halide that gives \( \ce{CH3CH2CH=CH2} \) on elimination?

\( \ce{CH3CH=CHCH3} \) (2-butene) with \( \ce{HCl} \) forms \( \ce{CH3CHClCH2CH3} \), which eliminates \( \ce{HCl} \) with alcoholic \( \ce{KOH} \) to form 1-butene (\( \ce{CH3CH2CH=CH2} \)).

\( \ce{CH3CH=CHCH3} \)
\( \ce{CH2=CHCH2CH3} \)
\( \ce{CH3CH2CH=CH2} \)
\( \ce{CH3CH=CHCH2CH3} \)
1

What is the major product when \( \ce{CH3CH2CH2CH3} \) reacts with \( \ce{Br2} \) in UV light at 300°C?

Bromination of butane at high temperature favors the more stable secondary radical, forming \( \ce{CH3CHBrCH2CH3} \) (2-bromobutane) as the major product.

\( \ce{CH3CH2CH2CH2Br} \)
\( \ce{CH2BrCH2CH2CH3} \)
\( \ce{CH3CHBrCH2CH3} \)
\( \ce{CH3CH2CHBrCH2} \)
3

Which of the following gives a yellow precipitate with \( \ce{AgNO3} \) in ethanol?

Alkyl iodides like \( \ce{CH3CH2I} \) react with \( \ce{AgNO3} \) to form \( \ce{AgI} \), a yellow precipitate, due to easy ionization.

\( \ce{CH3CH2Cl} \)
\( \ce{CH3CH2Br} \)
\( \ce{C6H5Cl} \)
\( \ce{CH3CH2I} \)
4

Which halide yields \( \ce{CH3CH2CH=CHCH2CH3} \) as the major product with alcoholic \( \ce{KOH} \) at 80°C?

Elimination (E2) of \( \ce{CH3CH2CHBrCH2CH2CH3} \) with alcoholic \( \ce{KOH} \) forms \( \ce{CH3CH2CH=CHCH2CH3} \) (3-hexene) per Zaitsev’s rule.

\( \ce{CH3CH2CHBrCH2CH2CH3} \)
\( \ce{CH3CH2CH2CH2CH2CH2Br} \)
\( \ce{CH3CH2CH2CHBrCH2CH3} \)
\( \ce{CH2BrCH2CH2CH2CH2CH3} \)
1

Which halide forms \( \ce{CH3CH2CH2CH=CH2} \) when treated with alcoholic \( \ce{KOH} \) at high temperature?

Elimination (E2) of \( \ce{CH3CH2CH2CH2CH2Br} \) (1-bromopentane) with alcoholic \( \ce{KOH} \) forms 1-pentene (\( \ce{CH3CH2CH2CH=CH2} \)).

\( \ce{CH3CH2CH2CH2CH2Br} \)
\( \ce{CH3CH2CH2CHBrCH3} \)
\( \ce{CH3CH2CH=CHCH2Br} \)
\( \ce{CH3CHBrCH2CH2CH3} \)
1

How many chlorine atoms are present in the product when benzene reacts with excess \( \ce{Cl2} \) in sunlight?

Benzene (\( \ce{C6H6} \)) with excess \( \ce{Cl2} \) in sunlight forms hexachlorocyclohexane (\( \ce{C6H6Cl6} \)), which has 6 chlorine atoms.

2
4
6
3
3

Which compound is formed when aniline reacts with \( \ce{NaNO2} \) and \( \ce{HCl} \), followed by \( \ce{KI} \)?

Aniline forms a diazonium salt with \( \ce{NaNO2} \) and \( \ce{HCl} \), which reacts with \( \ce{KI} \) to form \( \ce{C6H5I} \) (iodobenzene).

\( \ce{C6H5Cl} \)
\( \ce{C6H5Br} \)
\( \ce{C6H5I} \)
\( \ce{C6H6} \)
3

Which of the following has the highest boiling point?

Boiling point increases with molecular weight due to stronger London forces. \( \ce{CH3CH2I} \) has the highest molecular weight among the options.

\( \ce{CH3CH2F} \)
\( \ce{CH3CH2I} \)
\( \ce{CH3CH2Cl} \)
\( \ce{CH3CH2Br} \)
2

Which halide is most reactive with alcoholic \( \ce{KOH} \) to form an alkene?

Elimination (E2) with alcoholic \( \ce{KOH} \) favors tertiary halides due to stable alkene formation. \( \ce{(CH3)3CBr} \) reacts fastest.

\( \ce{CH3CH2Br} \)
\( \ce{(CH3)3CBr} \)
\( \ce{CH3CHBrCH3} \)
\( \ce{CH3Br} \)
2

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