Correct answer Carries: 4.
Wrong Answer Carries: -1.
What is the oxidation number of sulfur in \( \ce{S2O3^2-} \)?
Let S = \( x \). O = -2. Equation: \( 2x + 3(-2) = -2 \), \( 2x - 6 = -2 \), \( 2x = 4 \), \( x = +2 \) (average).
Which reaction demonstrates reduction by the removal of oxygen from a metal oxide without hydrogen involvement?
In \( \ce{PbO2 + C -> Pb + CO2} \), Pb (+4 in \( \ce{PbO2} \)) loses oxygen to become 0, reduced by C (0 to +4), no hydrogen present.
In the reaction \( \ce{Zn + CuSO4 -> ZnSO4 + Cu} \), which species is reduced?
Reduction involves gain of electrons. Here, \( \ce{Cu^2+} \) from \( \ce{CuSO4} \) gains 2 electrons to form \( \ce{Cu} \) (oxidation state 0), indicating reduction.
In the reaction \( \ce{2Cr + 3CuCl2 -> 2CrCl3 + 3Cu} \), which species is reduced?
Reduction involves electron gain. Cu (+2 in \( \ce{CuCl2} \)) gains electrons to become Cu (0).
In the reaction \( \ce{I2 + 5Cl2 + 6H2O -> 2HIO3 + 10HCl} \), how many electrons are transferred per iodine atom?
I (0 in \( \ce{I2} \)) becomes +5 in \( \ce{HIO3} \). Per I atom: 0 to +5 = 5 electrons.
In the reaction \( \ce{2KI + H2O2 -> I2 + 2KOH} \), which species acts as the oxidizing agent?
The oxidizing agent is reduced. \( \ce{H2O2} \) (O: -1) gains electrons to form \( \ce{OH^-} \) (O: -2), oxidizing \( \ce{I^-} \) to \( \ce{I2} \).
What is the oxidation number of technetium in \( \ce{Tc2O7} \)?
Let Tc = \( x \). O = -2. Equation: \( 2x + 7(-2) = 0 \), \( 2x - 14 = 0 \), \( x = +7 \).
Which reaction involves the addition of oxygen to a metal?
In \( \ce{4Na + O2 -> 2Na2O} \), Na gains oxygen to form \( \ce{Na2O} \), an oxidation process.
What is the change in oxidation number of sulfur in the reaction \( \ce{2H2S + O2 -> 2S + 2H2O} \)?
S (-2 in \( \ce{H2S} \)) becomes 0 in \( \ce{S} \). Change = 0 - (-2) = +2.
What is the oxidation number of phosphorus in \( \ce{PCl3} \)?
Let P = \( x \). Cl = -1. Equation: \( x + 3(-1) = 0 \), \( x - 3 = 0 \), \( x = +3 \).
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