For \( 7 \, \text{kg} \): \( 7g - T = 7a \Rightarrow 70 - T = 7a \).
For \( 5 \, \text{kg} \): \( T - mg \sin 37^\circ - f_k = 5a \).
\( N = mg \cos 37^\circ = 5 \times 10 \times 0.8 = 40 \, \text{N} \).
Friction: \( f_k = 0.2 \times 40 = 8 \, \text{N} \).
\( mg \sin 37^\circ = 50 \times 0.6 = 30 \, \text{N} \).
Net force: \( T - 30 - 8 = 5a \Rightarrow T - 38 = 5a \).
Solve: \( 70 - T = 7a \), \( T - 38 = 5a \).
Substitute: \( 70 - (5a + 38) = 7a \Rightarrow 70 - 38 - 5a = 7a \Rightarrow 32 = 12a \).
\( a = \frac{32}{12} \approx 2.67 \, \text{m/s}^2 \).
\( T - 38 = 5 \times 2.67 \Rightarrow T - 38 \approx 13.35 \Rightarrow T \approx 51.35 \, \text{N} \).