A copper wire of length \( 2 \, \text{m} \) and cross-sectional area \( 2 \times 10^{-6} \, \text{m}^2
\) carries a current of \( 2 \, \text{A} \). If the number density of free electrons in copper is \( 8.5
\times 10^{28} \, \text{m}^{-3} \) and \( e = 1.6 \times 10^{-19} \, \text{C} \), what is the drift
speed of the electrons?
Drift speed is given by \( v_d = \frac{I}{n e A} \).
Given: \( I = 2 \, \text{A} \), \( n = 8.5 \times 10^{28} \, \text{m}^{-3} \), \( e = 1.6 \times 10^{-19}
\, \text{C} \), \( A = 2 \times 10^{-6} \, \text{m}^2 \).
Substitute: \( v_d = \frac{2}{8.5 \times 10^{28} \times 1.6 \times 10^{-19} \times 2 \times 10^{-6}} \).
Calculate: \( v_d = \frac{2}{2.72 \times 10^4} = 7.35 \times 10^{-5} \, \text{m/s} \).
\( 5.0 \times 10^{-5} \, \text{m/s} \)
\( 7.35 \times 10^{-5} \, \text{m/s} \)
\( 8.0 \times 10^{-5} \, \text{m/s} \)
\( 9.5 \times 10^{-5} \, \text{m/s} \)