Correct answer Carries: 4.
Wrong Answer Carries: -1.
What is the frequency of a photon emitted when an electron drops from \( n = 2 \) to \( n = 1 \) in a hydrogen atom? (Use \( h = 6.6 \times 10^{-34} \, \text{J·s} \), 1 eV = \( 1.6 \times 10^{-19} \, \text{J} \))
\( \Delta E = 10.2 \, \text{eV} = 1.632 \times 10^{-18} \, \text{J} \).
\( \nu = \frac{\Delta E}{h} = \frac{1.632 \times 10^{-18}}{6.6 \times 10^{-34}} \approx 2.47 \times 10^{15} \, \text{Hz} \).
In Rutherford’s scattering experiment, what causes the large deflection of some alpha-particles?
Large deflections occur due to the strong repulsive force from the positively charged nucleus when alpha-particles approach it closely.
What is a limitation of Bohr’s model when applied to the hydrogen atom’s spectrum?
Bohr’s model cannot explain the relative intensities of spectral lines, as it does not account for transition probabilities.
Which of the following statements is correct about the absorption process in a hydrogen atom?
Absorption occurs when an electron jumps to a higher energy level by absorbing a photon matching the energy difference between levels.
What is the frequency of a photon emitted when an electron drops from \( n = 3 \) to \( n = 1 \) in a hydrogen atom? (Use \( h = 6.6 \times 10^{-34} \, \text{J·s} \), 1 eV = \( 1.6 \times 10^{-19} \, \text{J} \))
\( \Delta E = 12.09 \, \text{eV} = 1.9344 \times 10^{-18} \, \text{J} \).
\( \nu = \frac{\Delta E}{h} = \frac{1.9344 \times 10^{-18}}{6.6 \times 10^{-34}} \approx 2.93 \times 10^{15} \, \text{Hz} \).
In Bohr’s model, what happens to the energy required to ionize a hydrogen atom as the electron’s orbit number increases?
As \( n \) increases, the energy becomes less negative (closer to zero), so less energy is required to ionize the atom from higher orbits.
In a hydrogen atom, the total energy of an electron in the \( n = 3 \) state is -1.51 eV. What is its potential energy?
\( E = K + U \), \( K = -E = 1.51 \, \text{eV} \).
\( U = -2K = -2 \times 1.51 = -3.02 \, \text{eV} \).
What is the orbital period of an electron in the \( n = 4 \) orbit if \( v_1 = 2.2 \times 10^6 \, \text{m/s} \) and \( r_1 = 5.3 \times 10^{-11} \, \text{m} \)?
\( v_4 = \frac{2.2 \times 10^6}{4} = 5.5 \times 10^5 \, \text{m/s} \).
\( r_4 = 16 \times 5.3 \times 10^{-11} = 8.48 \times 10^{-10} \, \text{m} \).
\( T = \frac{2\pi r_4}{v_4} = \frac{2 \times 3.14 \times 8.48 \times 10^{-10}}{5.5 \times 10^5} \approx 9.68 \times 10^{-15} \, \text{s} \).
What assumption in Rutherford’s model contradicts classical electromagnetic theory?
Rutherford assumes electrons orbit the nucleus like planets, but classical theory predicts they would radiate energy and collapse, not remain stable.
In the Bohr model, how many de Broglie wavelengths fit into the circumference of the \( n = 3 \) orbit?
\( 2\pi r_n = n\lambda \).
For \( n = 3 \), number of wavelengths = 3.
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