Correct answer Carries: 4.
Wrong Answer Carries: -1.
A material with \( \mu_r = 250 \) and \( H = 700 \, \text{A m}^{-1} \) has \( B \): (Take \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m A}^{-1} \)).
\( B = \mu_0 \mu_r H \).
Given: \( \mu_r = 250 \), \( H = 700 \, \text{A m}^{-1} \), \( \mu_0 = 4\pi \times 10^{-7} \).
\( B = 4\pi \times 10^{-7} \times 250 \times 700 = 0.2198 \, \text{T} \approx 0.22 \, \text{T} \).
The magnetic field contribution \( B_m \) due to a material with \( M = 2.5 \times 10^5 \, \text{A m}^{-1} \) is: (Take \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m A}^{-1} \)).
\( B_m = \mu_0 M \).
Given: \( M = 2.5 \times 10^5 \, \text{A m}^{-1} \), \( \mu_0 = 4\pi \times 10^{-7} \).
\( B_m = 4\pi \times 10^{-7} \times 2.5 \times 10^5 = 0.314 \, \text{T} \approx 0.31 \, \text{T} \).
A magnetic dipole experiences a torque of \( 0.02 \, \text{N m} \) in a field of \( 0.4 \, \text{T} \) at \( 90^\circ \). What is its magnetic moment?
\( \tau = m B \sin\theta \), so \( m = \frac{\tau}{B \sin\theta} \).
Given: \( \tau = 0.02 \, \text{N m} \), \( B = 0.4 \, \text{T} \), \( \theta = 90^\circ \), \( \sin 90^\circ = 1 \).
\( m = \frac{0.02}{0.4 \times 1} = 0.05 \, \text{A m}^2 \).
The magnetic field lines of a solenoid resemble those of a bar magnet because:
A solenoid’s field lines emerge from one end (acting as a north pole) and enter the other (acting as a south pole), mirroring a bar magnet’s dipole field pattern due to the cumulative effect of current loops behaving like a magnetic dipole.
The magnetic field lines of a bar magnet are closest together:
Magnetic field lines are closest together near the poles of a bar magnet, where the field strength is greatest, as the density of lines reflects the magnitude of the magnetic field.
A solenoid with 800 turns per meter and current \( 1.5 \, \text{A} \) has a core with \( \mu_r = 300 \). What is \( B \) inside? (Take \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m A}^{-1} \)).
\( B = \mu_0 \mu_r n I \).
Given: \( n = 800 \, \text{m}^{-1} \), \( I = 1.5 \, \text{A} \), \( \mu_r = 300 \), \( \mu_0 = 4\pi \times 10^{-7} \).
\( B = 4\pi \times 10^{-7} \times 300 \times 800 \times 1.5 = 0.452 \, \text{T} \approx 0.45 \, \text{T} \).
A magnetic dipole of moment \( 0.3 \, \text{A m}^2 \) is in a uniform field of \( 0.7 \, \text{T} \) at \( 30^\circ \). What is the torque on it?
Torque is \( \tau = m B \sin\theta \).
Given: \( m = 0.3 \, \text{A m}^2 \), \( B = 0.7 \, \text{T} \), \( \theta = 30^\circ \), \( \sin 30^\circ = 0.5 \).
Substitute: \( \tau = 0.3 \times 0.7 \times 0.5 = 0.105 \, \text{N m} \).
A bar magnet with original \( m = 3.0 \, \text{A m}^2 \) is cut along its length into two equal parts. What is \( m \) of each part?
When cut along its length, each part typically has half the original magnetic moment in standard problems.
Given: \( m = 3.0 \, \text{A m}^2 \).
Each part: \( m' = \frac{3.0}{2} = 1.5 \, \text{A m}^2 \).
Which material exhibits perfect diamagnetism with \( \chi = -1 \) and is used in levitating trains?
Superconductors exhibit perfect diamagnetism with \( \chi = -1 \) due to the Meissner effect and are used in applications like magnetically levitated trains.
A material placed in a magnetic field reduces the field inside it slightly due to:
Diamagnetic materials reduce the magnetic field inside them slightly because an external field induces weak currents that create an opposing magnetic moment, resulting in a small negative susceptibility and a minor field reduction.
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