Correct answer Carries: 4.
Wrong Answer Carries: -1.
What characteristic of a convex mirror makes it suitable for use as a rear-view mirror in vehicles?
A convex mirror always produces a virtual, erect, and diminished image, regardless of the object’s position. This provides a wide field of view, allowing drivers to see a larger area behind the vehicle, making it ideal for rear-view mirrors despite the reduced image size.
A telescope has an objective of focal length \( 120 \, \text{cm} \) and an eyepiece of focal length \( 4 \, \text{cm} \). What is its magnifying power?
Magnifying power: \( m = \frac{f_o}{f_e} \).
\( f_o = 120 \, \text{cm} \), \( f_e = 4 \, \text{cm} \).
\( m = \frac{120}{4} = 30 \).
An object is at a depth of \( 16 \, \text{cm} \) in water (\( n = 1.33 \)). What is the apparent depth?
Apparent depth = \( \frac{\text{real depth}}{n} \).
Real depth = \( 16 \, \text{cm} \), \( n = 1.33 \).
Apparent depth = \( \frac{16}{1.33} \approx 12.03 \, \text{cm} \).
What is the primary reason optical fibers are bent without losing light transmission efficiency?
Optical fibers maintain light transmission when bent because the angle of incidence at the core-cladding interface remains greater than the critical angle, ensuring total internal reflection. This allows light to follow the bend without escaping into the cladding.
A ray of light passes from glass (\( n = 1.5 \)) to air at an angle of incidence of \( 40^\circ \). What is the angle of refraction?
Snell’s law: \( n_1 \sin i = n_2 \sin r \).
Glass (\( n_1 = 1.5 \)), air (\( n_2 = 1 \)), \( i = 40^\circ \).
\( 1.5 \times \sin 40^\circ = 1 \times \sin r \).
\( \sin 40^\circ \approx 0.643 \Rightarrow 1.5 \times 0.643 \approx 0.964 \Rightarrow \sin r = 0.964 \).
\( r = \sin^{-1}(0.964) \approx 74.6^\circ \).
Critical angle: \( \sin i_c = \frac{1}{1.5} \approx 0.667 \), \( \sin 40^\circ < 0.667 \), so refraction occurs.
In a convex lens, why does the image transition from virtual to real as the object moves from inside to outside the focal point?
Inside the focal point, a convex lens diverges rays, forming a virtual image on the same side. Beyond the focal point, the lens converges rays to a point on the opposite side, forming a real image. This transition occurs as the object crosses the focal point, changing the ray behavior.
In a prism, what condition results in the minimum deviation of light?
In a prism, minimum deviation occurs when the angle of incidence equals the angle of emergence. This symmetry ensures the refracted ray inside the prism is parallel to the base, minimizing the deviation angle.
A telescope has an objective of focal length \( 200 \, \text{cm} \) and an eyepiece of focal length \( 10 \, \text{cm} \). What is its magnifying power?
\( f_o = 200 \, \text{cm} \), \( f_e = 10 \, \text{cm} \).
\( m = \frac{200}{10} = 20 \).
A ray of light passes from glass (\( n = 1.62 \)) to air at an angle of incidence equal to the critical angle. What is the angle of refraction?
Critical angle: \( \sin i_c = \frac{n_2}{n_1} = \frac{1}{1.62} \approx 0.617 \).
\( i_c = \sin^{-1}(0.617) \approx 38.1^\circ \).
At critical angle, angle of refraction = \( 90^\circ \).
Why does a reflecting telescope often use a secondary mirror in its design?
In a reflecting telescope (e.g., Cassegrain design), a secondary mirror redirects the light focused by the primary concave mirror through a hole in the primary mirror to the eyepiece. This allows a compact design with a long focal length, improving magnification and convenience of observation.
A concave lens of focal length \( 25 \, \text{cm} \) has an object placed \( 50 \, \text{cm} \) from it. What is the image distance?
Focal length: \( f = -25 \, \text{cm} \) (concave lens).
Object distance: \( u = -50 \, \text{cm} \).
Lens formula: \( \frac{1}{v} - \frac{1}{u} = \frac{1}{f} \).
\( \frac{1}{v} - \frac{1}{-50} = \frac{1}{-25} \Rightarrow \frac{1}{v} + \frac{1}{50} = \frac{1}{-25} \Rightarrow \frac{1}{v} = \frac{1}{-25} - \frac{1}{50} = \frac{-2 - 1}{50} = \frac{-3}{50} \).
\( v = -\frac{50}{3} \approx -16.67 \, \text{cm} \) (virtual image).
A telescope has an objective of focal length \( 100 \, \text{cm} \) and an eyepiece of focal length \( 5 \, \text{cm} \). What is its magnifying power?
\( f_o = 100 \, \text{cm} \), \( f_e = 5 \, \text{cm} \).
\( m = \frac{100}{5} = 20 \).
A double convex lens of refractive index \( 1.5 \) has radii of curvature \( 15 \, \text{cm} \) and \( -15 \, \text{cm} \). What is its focal length?
Lens maker’s formula: \( \frac{1}{f} = (n - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \).
\( n = 1.5 \), \( R_1 = 15 \, \text{cm} \), \( R_2 = -15 \, \text{cm} \).
\( \frac{1}{f} = (1.5 - 1) \left( \frac{1}{15} - \frac{1}{-15} \right) = 0.5 \left( \frac{1}{15} + \frac{1}{15} \right) = 0.5 \times \frac{2}{15} = \frac{1}{15} \).
\( f = 15 \, \text{cm} \).
In a convex mirror, what is the significance of the focal point being behind the mirror?
The focal point of a convex mirror is virtual and behind the mirror because reflected rays diverge and appear to originate from this point when traced backward. This indicates the mirror’s diverging nature, ensuring all images are virtual, erect, and diminished.
What is the key optical principle behind the working of a periscope?
A periscope uses total internal reflection in prisms (or plane mirror reflection) to redirect light. Prisms reflect light internally at angles greater than the critical angle, allowing the viewer to see objects from a different height or direction without direct line-of-sight.
Are you sure you want to submit your answers?